Okey, we are going to use the hlaf life formula, let's do it:
[tex]Nn=N_0(\frac{1}{2})^n[/tex]Where:
N=6
Nn = quantity remaining after n half-lifes
No = initial quantity=125
Replacing we obtain:
[tex]N_6=125(\frac{1}{2})^6=125(\frac{1}{64})\approx1.95[/tex]Finally we obtain that the radioactive isotope will have 1.95 grams after 6 half lives.
