Given the following inequality:
[tex]6\ge3p+9[/tex]to solve for 'p', first we can substract 9 from both sides to get:
[tex]\begin{gathered} 6-9\ge3p+9-9 \\ \Rightarrow-3\ge3p \end{gathered}[/tex]now, we can divide both sides by 3 to get the solution set for p. Notice that since we are dividing by a positive number, the orientation of the inequality sign will remain the same:
[tex]\begin{gathered} (-3\ge3p)\cdot\frac{1}{3} \\ \Rightarrow-\frac{3}{3}\ge p \\ \Rightarrow p\le-1 \end{gathered}[/tex]therefore, p <= -1
The graph of the solution would be the following:
