Solution
We have the following system of equations:
3.25x - 1.5 y= 1.25 (1)
13x -6y= 10 (2)
We can solve for x in the first equation and we got
[tex]x=\frac{1.25+1.5y}{3.25}[/tex]We can replace this into the second equation and we got:
[tex]13(\frac{1.25+1.5y}{3.25})-6y=10[/tex]Then we can solve for y on this way:
[tex]5+6y-6y=10[/tex]Since 5 is not equal to 10 then we can conclude that this system of equations has no solution
