The area of a circle is given by:
[tex]\begin{gathered} A=r^2\pi \\ \text{Where:} \\ r=\frac{8}{2}=4 \\ \text{ Since it is a semicircle, the area is:} \\ A=\frac{4^2\pi}{2}=8\pi \end{gathered}[/tex]
And the area of the triangle is:
[tex]\begin{gathered} A=\frac{b\cdot h}{2} \\ \text{where:} \\ b=8 \\ h=7 \\ A=\frac{8\cdot7}{2}=28 \end{gathered}[/tex]
Therefore, the total area is:
[tex]A_T=8\pi+28\approx53.13\operatorname{cm}[/tex]
