A regular die has six sides with numbers 1 up to 6.
Thus, there are 3 even numbers in the die which are 2, 4 and 6.
And there is only one side of the die that has the number 3.
This means that we are looking for 4 possibilities in rolling a die.
Computing the probability, we get:
[tex]\text{ Probability = }\frac{No.\text{ of even numbers + No. of 3s}}{Total\text{ possible numbers}}[/tex][tex]\text{ = }\frac{3\text{ + 1}}{6}[/tex][tex]\text{ = }\frac{4}{6}\text{ = }\frac{2}{3}[/tex][tex]\text{ Probability = }\frac{2}{3}[/tex]Therefore, the probability of getting a 3 or even number is 2/3.
Note:
For "or" scenario, the following equation must be applied:
[tex]\text{ Probability = }\frac{\text{ No. of outcomes for A}}{\text{Total number of outcomes}}\text{ + }\frac{\text{ No. of outcomes for B}}{\text{Total number of outcomes}}\text{ + }\ldots[/tex]For "and" scenario, the following equation must be applied:
[tex]\text{ Probability = }\frac{\text{ No. of outcomes for A}}{\text{Total number of outcomes}}\text{ x }\frac{\text{ No. of outcomes for B}}{\text{Total number of outcomes}}\text{ x }\ldots[/tex]