ANSWER:
2.99 meters per second
STEP-BY-STEP EXPLANATION:
Given:
m1 = 1.16 kg
m2 = 1.98 kg
Vi1 = 8.64 m/s
Vi2 = -3.34 m/s
Vf1 = -2.16 m/s
We can determine the speed of the second car thanks to the law of conservation of momentum which is the following:
[tex]m_1\cdot V_{i1}+m_2\cdot V_{i2}=m_1\cdot V_{f1}+m_2\cdot V_{f2}[/tex]
We replace each value and we would have:
[tex]\begin{gathered} 1.16\cdot8.64+1.98\cdot3.34=1.16\cdot-2.16+1.98\cdot V_{f2} \\ 3.4092=-2.5056+1.98\cdot V_{f2} \\ 1.98\cdot V_{f2}=3.4092+2.5056 \\ V_{f2}=\frac{5.9148}{1.98} \\ V_{f2}=2.99\text{ m/s} \end{gathered}[/tex]
The velocity of the second car is 2.99 meters per second
