The general form for the equation of a circle is given by:
[tex](x-x_0)^2+(y-y_0)^2=r^2...(1)[/tex]
Where (x₀, y₀) are the coordinates of the center, and r is the radius. From the problem, we identify:
[tex]\begin{gathered} (x_0,y_0)=(1,0) \\ r=3 \end{gathered}[/tex]
Finally, using (1):
[tex]\begin{gathered} (x-1)^2+(y-0)^2=3^2 \\ \\ \therefore(x-1)^2+y^2=9 \end{gathered}[/tex]
