Given the expression :
[tex]-5(x+2)+3x=\boxed{\square}[/tex]the equation has an infinite number of solutions
So, the left side must be equal the right side
So, simplify the left side:
[tex]\begin{gathered} -5(x+2)+3x \\ =-5x-10+3x \\ =-2x-10 \end{gathered}[/tex]We will check the option to see which one will give the previous result
• -5(x-3)+2x = -5x + 15 + 2x = -3x + 15 ,False
,•
,• -5x - 10 ,False
,•
,• x - 2x +2 + 3x = 2x + 2 ,False
,•
,• -2(x+5) = -2x - 10 ,True
So , the answer is option 4). -2(x+5)
