Answer
0.1667 L
Explanation
Given:
Let the volume of the concentrated HCl be V₁
The concentration of the concentrated HCl, C₁ = 12 M
The volume of the diluted HCl, V₂ = 2 L
The concentration of the diluted HCl, C₂ = 1 M
What to find:
The volume of the concentrated HCl, V₁ needed to make a 2L of 1M solution.
Solution:
The volume of the concentrated HCl, V₁ needed to make a 2L of 1M solution can be calculated using the dilution formula.
[tex]\begin{gathered} C_1V_1=C_2V_2 \\ \\ \Rightarrow V_1=\frac{C_2V_2}{C_1} \end{gathered}[/tex]Put C₁ = 12 M, V₂ = 2 L, and C₂ = 1 M into the formula to get V₁
[tex]V_1=\frac{1M\times2L}{12M}=\frac{2L}{12}=0.1667\text{ }L[/tex]Therefore, the volume of the concentrated HCl, V₁ needed to make a 2L of 1M solution is 0.1667 L
