We have two points that will help us to find the slope (m)
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]where
(-1,0)=(x1,y1)
(1,6)=(x2,y2)
then we substitute the values
[tex]m=\frac{6-0}{1+1}=\frac{6}{2}=3[/tex]If the y intercept is (0,3)
the slope-intercept form is
[tex]y=mx+b[/tex]where
m=slope=3
b=y-intercept= 3
[tex]y=3x+3[/tex]
