Respuesta :

[tex]\begin{gathered} \Rightarrow(3d+9)^2-64,\text{ where d=1} \\ \Rightarrow(3\times1+9)^2-64 \\ \Rightarrow(3+9)^2-64 \\ \Rightarrow12^2-64 \\ \Rightarrow144-64 \\ \Rightarrow80 \end{gathered}[/tex]