Given that the frequency of the first harmonic, f_1 = 330 Hz
We have to find the frequency of the second and third harmonics.
(a) The frequency of the second harmonic is
[tex]\begin{gathered} f_2=2f_1 \\ =2\times330 \\ =660\text{ Hz} \end{gathered}[/tex]The frequency of the third harmonic is
[tex]\begin{gathered} f_3=3f_1 \\ =3\times330 \\ =990\text{ Hz} \end{gathered}[/tex](b) The speed of sound in air is v = 344 m/s
Let the length of the air column be l.
The formula to calculate length is
[tex]l_{}=\frac{v}{2f_1}[/tex]Substituting the values, the length will be
[tex]\begin{gathered} l=\frac{344}{2\times330} \\ =0.521m\text{ } \end{gathered}[/tex]