These figures are similar. Thearea of one is given. Find thearea of the other.

Solution
- The solution steps are given below:
[tex]\begin{gathered} \text{ The formula for solving the qeustion is given below:} \\ \frac{l_1^2}{l_2^2}=\frac{A_1}{A_2} \\ \\ \text{ Let } \\ l_1=3 \\ l_2=6,A_2=24,A_1=? \\ \\ \frac{3^2}{6^2}=\frac{A_1}{24} \\ \\ \text{ Make }A_1\text{ the subject of the formula} \\ \\ A_1=\frac{3^2\times24}{6^2} \\ \\ A_1=6 \end{gathered}[/tex]Answer
The area of the smaller figure is 6in²