It is given that the line passes through the point (-3,-1) and the slope is -4.
The slope point form of equation of the line is given by:
[tex]y-y_1=m(x-x_1)[/tex]Here the point and slope are given as:
[tex](x_1,y_1)=(-3,-1),m=4[/tex]Therefore the equation is given by:
[tex]\begin{gathered} y-(-1)=-4(x-(-3)) \\ y+1=-4x-12 \\ 4x+y+13=0 \end{gathered}[/tex][tex]\text{Hence 4x+y+13=0 is the equation of the line.}[/tex]