The first step to answer this question is to convert the given mass (68g LiNO3) to moles using the molar mass of lithium nitrate:
[tex]68gLiNO_3\cdot\frac{1molLiNO_3}{68.946gLiNO_3}=0.98molLiNO_3[/tex]According to the given equation, 4 moles of LiNO3 produce 1 mole of Pb(NO3)4, the next step is to use this ratio to determine how many moles of Pb(NO3)4 are produced:
[tex]0.98molLiNO_3\cdot\frac{1molPb(NO_3)_4}{4molLiNO_3}=0.245molPb(NO_3)_4[/tex]It means that 0.245 moles of lead (IV) nitrate are produced.
