Step 1: Given the volume of the cone having base and height
Base = diameter = 16yrd
Diameter = 2 x radius
D= 2r
Height = 16yd
[tex]\begin{gathered} R\text{adius = }\frac{Diameter}{2}\text{ } \\ R\text{ = }\frac{D}{2}\text{ = }\frac{16yd}{2}\text{ = 8yd} \end{gathered}[/tex]
Step 2: Find the Volume of a cone having base and height
[tex]\begin{gathered} \text{Volume of a cone = }\frac{1}{3}\pi^{}r^2h \\ V\text{ = }\frac{1}{3}\text{ }\times\text{ }\frac{22}{7}\text{ }\times\times(8yd)^2\times\text{ 16yd} \\ V\text{ = }\frac{22528}{21}yd^3 \\ V=1072.76yd^{3\text{ }} \\ V=1072.8yd^3 \end{gathered}[/tex]
Hence the Volume of a cone = 1072.8yd³
