Given the following equation:
[tex]x^2=4(x-9)[/tex]
First of all, we note that the quadratic equation is written in the general form shown below;
[tex]ax^2+bx+c=0[/tex]
We shall now attempt to re-write the equation given in the form shown above. This is shown as follows;
[tex]\begin{gathered} x^2=4(x-9)_{} \\ We\text{ shall now expand the parenthesis;} \\ x^2=4x-36 \\ We\text{ shall now collect all like terms;} \\ \text{Subtract 4x and add 36 to both sides to both sides} \end{gathered}[/tex][tex]\begin{gathered} x^2-4x+36=4x-4x-36+36 \\ x^2-4x+36=0 \end{gathered}[/tex]
We now have our quadratic equation as shown above.
Comparing this with the general form of a quadratic equation, we can now identify a, b and c as follows;
[tex]\begin{gathered} a=1 \\ b=-4 \\ c=36 \end{gathered}[/tex]
ANSWER:
a = 1
b = -4 and
c = 36
