ANSWER:
A. F > 48.02 N
B. F < 48.02 N
C. F = 48.02 N
STEP-BY-STEP EXPLANATION:
Given:
Mass (m) = 7 kg
µ = 0.7
Balancing horizontal forces:
[tex]\begin{gathered} F=\mu N+ma\rightarrow F=\mu\cdot m\cdot g+ma \\ \text{ We replacing} \\ F=0.7\cdot7\cdot9.8+7a \\ F=48.02+7a \\ a=\frac{F-48.02}{7} \end{gathered}[/tex]A. The block is speeding up
It means the block is having a positive value of acceleration:
[tex]\begin{gathered} a>0 \\ \frac{F-48.02}{7}>0 \\ F>48.02\text{ N} \end{gathered}[/tex]B. The block is slowing down
[tex]\begin{gathered} a<0 \\ \frac{F-48.02}{7}<0 \\ F<48.02\text{ N} \end{gathered}[/tex]C. The block is moving at a constant speed
[tex]\begin{gathered} a=0 \\ \frac{F-48.02}{7}=0 \\ F=48.02\text{ N} \end{gathered}[/tex]