Answer:
72.66g of Fe2O3 are produced.
Explanation:
1st) From the balanced equation we know that 2 moles of Fe2O3 are produced from 4 moles of iron (Fe). With a mathematical rule of three we can calculate the moles of Fe2O3 that will be produced from 0.89 moles of iron:
[tex]\begin{gathered} 4molesFe-2molesFe_2O_3 \\ 0.89molesFe-x=\frac{0.89molesFe*2molesFe_2O_3}{4molesFe} \\ x=0.445molesFe_2O_3 \end{gathered}[/tex]Now we know that 0.455 moles of Fe2O3 are produced.
2nd) Now we have to convert 0.455 moles of Fe2O3 into grams, by using the molar mass of Fe2O3 (159.7g/mol):
[tex]0.455moles*\frac{159.7g}{1mole}=72.66g[/tex]So, 72.66g of Fe2O3 are produced.
