Answer:
7,396.
Explanation:
Given that we want to find how many randomly selected sales transactions must be surveyed to determine the percentage that transpired over the Internet.
Given;
Confidence interval = 99%
Z value = 2.58
Margin of error ME=3% =0.03
Applying the formula;
[tex]n=\frac{z^2}{ME^2}[/tex]Substituting the values;
[tex]\begin{gathered} n=\frac{2.58^2}{0.03^2} \\ n=\frac{6.6564}{0.0009} \\ n=7,396 \end{gathered}[/tex]Therefore, the number of randomly selected sales transactions that must be surveyed to determine the percentage that transpired over the Internet is 7,396.