SOLUTION
Now, the total number of students = 55
Total number of female students = 32
Total number of students with B = 8
Total number of students that are female and scored B = 5
Now, Let the
[tex]The\text{ probability of female students = Pr(F)}[/tex][tex]and\text{ the probability of a student scoring B = Pr(B)}[/tex][tex]\begin{gathered} \text{Also the probability of that a student is female and scores B } \\ be\text{ Pr(F}\cap B) \end{gathered}[/tex]Then the Probability that a student was female or scored B becomes
[tex]Pr(F)+Pr(B)-Pr(F\cap B)[/tex]This becomes
[tex]\begin{gathered} \frac{32}{55}+\frac{8}{55}-\frac{5}{55} \\ \\ \frac{32+8-5}{55} \\ \\ \frac{35}{55} \\ \\ 0.636 \end{gathered}[/tex]