let's find y
[tex]\frac{6}{2}-\frac{y}{2}=y[/tex][tex]\text{add }\frac{1}{2}y\text{ to both sides}[/tex][tex]\frac{6}{2}-\frac{1}{2}y+\frac{1}{2}y=y+\frac{1}{2}y[/tex]Therefore,
[tex]\begin{gathered} 3=\frac{2y+y}{2} \\ 3=\frac{3}{2}y \end{gathered}[/tex]cross multiply
[tex]\begin{gathered} 3\times2=3y \\ 6=3y \\ y=\frac{6}{3} \\ y=2 \end{gathered}[/tex]