1) Balance the chemical equation.
[tex]CH_3OH+O_2\rightarrow CO_2+H_2O[/tex]2) List the elements in the reactant and in the products.
Reactants:
C: 1
H: 4
O: 3
Products:
C: 1
H: 2
O: 3
BalanceH.
[tex]CH_3OH+O_2\operatorname{\rightarrow}CO_2+2H_2O[/tex]Reactants:
C: 1
H: 4
O: 3
Products:
C: 1
H: 4
O: 4
Balance oxygen
[tex]CH_3OH+\frac{3}{2}O_2\operatorname{\rightarrow}CO_2+2H_2O[/tex]Multiply every coefficient by the denominator
[tex]2CH_3OH+3O_2\operatorname{\rightarrow}2CO_2+4H_2O[/tex]Reactants:
C: 2
H: 8
O: 8
Products:
C: 2
H: 8
O: 8
3) Moles of CH3OH needed to produce 3 mol CO2.
The molar ratio between CH3OH and CO2 is 2 mol CH3OH: 2 mol CO2.
[tex]mol\text{ }CH_3OH=3\text{ }mol\text{ }CO_2*\frac{2\text{ }mol\text{ }CH_3OH}{2\text{ }mol\text{ }CO_2}[/tex][tex]mol\text{ }CH_3OH=3\text{ }mol\text{ }CH_3OH[/tex]The moles of CH3OH needed are 3 mol.
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