Respuesta :
Answer:
5.6 moles
Explanations:
Given the decomposition of hydrazine to produce ammonia and nitrogen expressed as:
[tex]N₂H₄\left(l\right)→NH₃\left(g\right)+N₂\left(g\right)[/tex]The balanced form of the equation is expressed as:
[tex]3N_2H_4(l)\rightarrow4NH_3(g)+N_2(g)[/tex]According to stochiometry, 3 moles of N₂H₄ produce 4 moles of NH₃, since there are 4.2 moles of N₂H₄ that react, the number of moles of NH₃ that will be produced is given as:
[tex]\begin{gathered} moles\text{ of NH}_3=4.2moles\times\frac{4}{3} \\ moles\text{ of NH}_3=1.4\times4 \\ moles\text{ of NH}_3=5.6moles \end{gathered}[/tex]Hence the moles of NH₃ that form when 4.2 moles of N₂H₄ completely reacts is 5.6moles
