Answer:
The x-intercept is at;
[tex]\begin{gathered} x=2 \\ (2,0) \end{gathered}[/tex]The y-intercept is at;
[tex]\begin{gathered} y=4.5 \\ (0,4.5) \end{gathered}[/tex]Explanation:
Given the equation:
[tex]4y+9x=18[/tex]We want to find the x and y intercept of the equation;
Recall that the x intercept is at y=0;
[tex]\begin{gathered} 4y+9x=18 \\ at\text{ y=0} \\ 4(0)+9x=18 \\ 9x=18 \\ x=\frac{18}{9} \\ x=2 \\ (2,0) \end{gathered}[/tex]Also, the y intercept is at x=0;
[tex]\begin{gathered} 4y+9x=18 \\ at\text{ x=0} \\ 4y+9(0)=18 \\ 4y=18 \\ y=\frac{18}{4} \\ y=4.5 \\ (0,4.5) \end{gathered}[/tex]Therefore, The x-intercept is at;
[tex]\begin{gathered} x=2 \\ (2,0) \end{gathered}[/tex]The y-intercept is at;
[tex]\begin{gathered} y=4.5 \\ (0,4.5) \end{gathered}[/tex]