1. Use the graph of f(x) to evaluate part a, b and c below. f(x) 5 4+ 3+ 2+ 1 1 2 3 4 -4 -3 -2 -1 0 -1 - 2t a. Find f (2) b: Find f(-2) c. Find f(x) = 1)

1 Use the graph of fx to evaluate part a b and c below fx 5 4 3 2 1 1 2 3 4 4 3 2 1 0 1 2t a Find f 2 b Find f2 c Find fx 1 class=

Respuesta :

f(2) = 3

f(-2) = 4

x = 1

Explanation:

This is a piece wise function and we need to indicate the domainand range for each function:

Note y = f(x)

The curve represent y = x² for values of x ≤ 1

The straight horizontal line represent y = 3 for values of x > 1 but ≤ 2

y = 3, for 1 < x ≤ 2

The slant straight line represent y = x for x > 2 but extends to infinity

y = x for x > 2

f(2): this means we should find the value of f(x) when x = 2

From the above, x =2 when y = f(x) = 3

Hence, f(2) = 3

f(-2): this means we should find the value of f(x) when x = -2

From the above, x = -2 when y = f(x) = x²

f(-2) = (-2)² = 4

Hence, f(-2) = 4

f(x) = 1

This means we should find the value of x when f(x) =1

f(x) = 1, when y = x²

f(x) = x²

we inset the value of f(x) into the equation:

1 = x²

x = √1

x = 1

Hence, f(x) =1 when x = 1