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[tex]\begin{gathered} 8\frac{1}{6}-3\frac{5}{6} \\ \text{Convert to improper fractions} \\ =\frac{49}{6}-\frac{23}{6} \\ =\frac{49-23}{6} \\ =\frac{26}{6} \\ =4\frac{2}{6} \\ =4\frac{1}{3} \end{gathered}[/tex]The answer is four and one thirds
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