To solve the equation, we can first get all the terms without x to the right side and all the terms with x to the lesft side.
We start by substracting 2 from both sides:
[tex]\begin{gathered} 5x+2=3x+40 \\ 5x+2-2=3x+40-2 \\ 5x=3x+38 \end{gathered}[/tex]
Now, we substract 3x from both sides:
[tex]\begin{gathered} 5x=3x+38 \\ 5x-3x=3x-3x+38 \\ 2x=38 \end{gathered}[/tex]
Now that we have only terms with x on the left side and only terms without x on the right side, we can finish the solve by dividing both sides by 2:
[tex]\begin{gathered} 2x=38 \\ \frac{2x}{2}=\frac{38}{2} \\ x=19 \end{gathered}[/tex]
So, the solutions set is {19}.
