Answer:
Explanation:
Here, we want to write an acidic ratio
We start by balancing the ionic equation as follows:
[tex]4Zn_{(s)}+NO^-_{3(aq)}+10H^+_{}\text{ }\rightarrow NH^+_{4(aq)}+4Zn^{2+}_{(aq)}+3H_2O^{}_{}[/tex]From what we have here, we have to check for the balance in terms of the number of atoms and the ions
From the balanced equation, we can see that 4 atoms of zinc reacts with a single ionic entity of the nitrate V
We have the ratio as:
[tex]\frac{4}{1}\text{ = 4}[/tex]
