To factor this expression we need to find the common factor and take it out
In the two terms above the bracket (k - 3) is a common factor, because it is repeated in the two terms, then let us take it
[tex]7k(k-3)+4(k-3)=(k-3)\lbrack7k+4\rbrack[/tex]There is no like term in the bracket [7k + 4], then the answer is
(k - 3)[7k + 4]
13.
[tex]3y(2y+3)-5(2y+3)[/tex]The common factor of the two terms is the bracket (2y + 3), then we will take it
[tex]3y(2y+3)-5(2y+3)=(2y+3)\lbrack3y-5\rbrack[/tex]No like terms in the bracket [3y-5], then
The answer is (2y+3)[3y-5]
