Respuesta :
Solution:
Number 5:
The diameter of the Ferris wheel is given as
[tex]d=190ft[/tex]The formula to calculate the distance of one revolution is given below as
[tex]\begin{gathered} C=2\pi r \\ \pi=3.14 \\ r=\frac{190}{2}ft=95ft \end{gathered}[/tex]By substituting the values, we will have
[tex]\begin{gathered} C=2\pi r \\ C=2\times3.14\times95ft \\ C=596.6ft \end{gathered}[/tex]For three revolutions, we will have the distance to be
[tex]\begin{gathered} D=596.6ft\times3 \\ D=1789.8ft \end{gathered}[/tex]Hence,
The distance he will travel in those 3 revolutions is
[tex]\Rightarrow1789.8ft[/tex]Number 4:
The formula for the area of a sector is given below as
[tex]\begin{gathered} A=\frac{\theta}{360}\times\pi r^2 \\ A=\frac{8}{360}\times3.14\times(95)^2 \\ A=629.74ft^2 \end{gathered}[/tex]Hence,
The area of the sector to the nearest hundredth is
[tex]\Rightarrow629.74ft^2[/tex]