Given
[tex]x^0yz^{-3}[/tex]Solution
Recall
[tex]a^0=1[/tex][tex]\begin{gathered} x^0yz^{-3} \\ 1.yz^{-3} \end{gathered}[/tex][tex]yz^{-3}[/tex]Recall
[tex]\begin{gathered} a^{-b}=\frac{1}{a^b} \\ so\text{ }z^{-3}=\frac{1}{z^3} \end{gathered}[/tex]Therefore
[tex]yz^{-3}=\frac{y}{z^3}[/tex]The final answer
[tex]x^0yz^{-3}=\frac{y}{z^3}[/tex]