Respuesta :

Solution

[tex]y=\frac{\sqrt[]{x}}{\sqrt[]{x+2}}[/tex]

For this case we can do the following:

[tex]y=\sqrt[]{\frac{x}{x+2}}[/tex]

The minimum value should be 0 for y assuming that x>= 0

Then the range should be:

[tex]0\le y<1[/tex]

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