Respuesta :

Hello there. To solve this question, we have to remember some properties about equations of circles.

Given the following equation:

[tex](x-x_0)^2+(y-y_0)^2=R^2[/tex]

It is called the equation of a circle with center at

[tex](x_0,\,y_0)[/tex]

And radius R.

In the question, it gives us two equations that we might describe the shape of the equation, considering its key features (center, foci, asymptotes, semi-major and semi-minor axes, if applicable).

We have that

[tex](x+4)^2+(y-2)^2=16[/tex]

Is the equation of a circle with center at (-4, 2) and radius equal to

[tex]R=\sqrt{16}=4[/tex]

For the other equation

[tex](x-2)^2+(y-5)^2=64[/tex]

Is also the equation of a circle, with center at (2, 5) and radius equal to

[tex]R=\sqrt{64}=8[/tex]