Determine if it opens up or down and find the axis of symmetry

Statement Problem: Determine if it opens up or down and find the axis of symmetry. Given the function;
[tex]f(x)=-2x^2+12x-15[/tex]Solution:
The graph of the function is;
Thus, from the graph. It shows it opens down.
The axis of symmetry is;
[tex]x=-\frac{b}{2a}[/tex]From the given function;
[tex]\begin{gathered} f(x)=ax^2+bx+c \\ f(x)=-2x^2+12x-15 \\ a=-2,b=12,c=-15 \end{gathered}[/tex]Thus, the axis of symmetry is;
[tex]\begin{gathered} x=-\frac{12}{2(-2)} \\ x=-\frac{12}{-4} \\ x=3 \end{gathered}[/tex]