The bushing shown in the figure weighs 0.2833 pounds per cubic inches.
The bushing shows is a hollow cylinder, the volume of a hollow cylinder is :
[tex]V=\frac{\pi(D^2_o-D^2_i)}{4}\times h[/tex]
where Do is the outer diameter
Di is the inner diameter
h is the height of the cylinder
From the problem,
Di = 2 and 1/4 inches or 2.25 in
Do = 6 inches
h = 7 and 1/4 inches or 7.25 in
Using the formula above :
[tex]\begin{gathered} V=\frac{\pi(6^2-2.25^2)}{4}\times7.25 \\ V=176.16in^3 \end{gathered}[/tex]
The volume is 176.16 cubic inches
Multiply this to the given weight per cubic inches.
[tex]176.16\times0.2833=49.906[/tex]
The weight is 49.9 pounds
The answer is 49.9 pounds
