contestada

An advertisement for jelly beans claims "At least 100 beans in every box.". The machine used to fill the boxes has been found to fill boxes with a mean of 108 beans and a standard deviation of 3 beans. What is the probability that the advertising claim is true?Choose one answer. a. 0.996b. 0.998c. 0.500d. 0.994

Respuesta :

[tex]\begin{gathered} \mu=108 \\ \sigma=3 \end{gathered}[/tex]

So,

[tex]\begin{gathered} P(X\ge100)=P(Z\ge\frac{X-\mu}{\sigma})=P(Z\ge\frac{100-108}{3}) \\ so: \\ P(Z\ge-\frac{8}{3}) \end{gathered}[/tex]

Using the z-table:

[tex]P(Z\ge-\frac{8}{3})\approx0.9962[/tex]

Answer:

a. 0.996

Otras preguntas