Answer: x less equal to 0
[tex]0\ge\times[/tex]Step by step solution:
To solve the inequality:
[tex]-6(1+2x)\ge6(2x-1)+2x[/tex]We start by taking out the parenthesis:
[tex]-6-12x\ge12x-6+2x[/tex]We are going to add +12 on both sides:
[tex]\begin{gathered} -6-12x+12x\ge12x-6+2x+12x \\ -6\ge26x-6 \end{gathered}[/tex]Adding +6 to each of the sides, left and right, to maintain the balance of the inequality, each operation must be performed on both sides:
[tex]\begin{gathered} -6+6\ge26x-6+6 \\ 0\ge26x \end{gathered}[/tex]Now we divide each side by 1/26:
[tex]\begin{gathered} \frac{0}{26}\ge\frac{26x}{26} \\ 0\ge x \end{gathered}[/tex]
