Given:
The expression
[tex](4^{-1}\times2^{-1})\times3^{-1}[/tex]
Required:
Find the value.
Explanation:
We will use exponent rule
[tex]a^{-1}=\frac{1}{a}[/tex]
Now,
[tex]\begin{gathered} =(4^{-1}\times2^{-1})\times3^{-1} \\ =(\frac{1}{4}\times\frac{1}{2})\times\frac{1}{3} \\ =\frac{1}{8}\times\frac{1}{3} \\ =\frac{1}{24} \end{gathered}[/tex]
Answer:
[tex]\text{ The value is }\frac{1}{24}.[/tex]
