Solve for a.- 4a + 26 ≤ 2Oaz-7O a≥6Oa≥-6○ a ≤ 6

Given the inequality:
[tex]-4a+26\leq2[/tex]You can solve for "a" as follows:
1. Apply the Subtraction Property of Inequality by subtracting 26 from both sides of the inequality:
[tex]-4a+26-(26)\leq2-(26)[/tex][tex]-4a\leq-24[/tex]2. Apply the Division Property of Inequality by dividing both sides by -4. As you are dividing both sides by a negative number, the direction of the inequality symbol changes:
[tex]\begin{gathered} \frac{-4a}{-4}\ge\frac{-24}{-4} \\ \\ a\ge6 \end{gathered}[/tex]Hence, the answer is: Second option.