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2. The hare has challenged the tortoise to arace. The hare offers the tortoise a 435-meter head start. Therace path is 500 meters long, and the tortoise moves at a rate of 5 meters per minute. The hare knows thathe moves at a rate of 30 times as fast as the tortoise.a. Write functions g(t) and h(t) that represent the distance, d in meters, the tortoise and the hare,respectively, have traveled t minutes after the hare begins running.b. Graph the two equations from part a.

Respuesta :

Hello!

First, let's draw this situation to understand it better:

We know that the tortoise has a velocity of 5 meters per minute, and th hare has 30 times hi velocity. So, we have:

• Tortoise,: 5m/min

,

• Hare,: 150m/min

We know thatthe tortoise starts iat he point 435m, while the hare starts iat oint 0m. So, we an write the functions as:

g(tortoise) =

[tex]\begin{gathered} g(t)=5t+435\text{ \lparen tortoise\rparen} \\ h(t)=150t\text{ \lparen hare\rparen} \end{gathered}[/tex]

Now, let's graph these two equations:

g(t) (tortoise):

h(t) (hare):

Ver imagen LakshI656056
Ver imagen LakshI656056
Ver imagen LakshI656056

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