Given data:
Initial velocity of the projectile;
[tex]u=25.0\text{ m/s}[/tex]Launch angle;
[tex]\theta=38.0\degree[/tex]The range of the projectile is given as,
[tex]R=\frac{u^2\sin (2\theta)}{g}[/tex]Here, g is the acceleration due to gravity.
Substituting all known values,
[tex]\begin{gathered} R=\frac{(25\text{ m/s})^2\times\sin (2\times38\degree)}{(9.81\text{ m/s}^2)} \\ \approx61.8\text{ m} \end{gathered}[/tex]Therefore, the balloon will hit the ground 61.8 m away from the launcher.
