B
1) As we have some dimensions and the area of both parallelograms. Let's use the Area of a parallelogram to find out which one has a taller height:
A)
[tex]\begin{gathered} A=b\cdot h \\ 60=10h \\ h=\frac{60}{10} \\ h=6\text{ m} \end{gathered}[/tex]As for B we have:
[tex]\begin{gathered} A_B=b\cdot h \\ 40=4h \\ h=\frac{40}{4} \\ h=10 \end{gathered}[/tex]2) Hence the tallest parallelogram is the B parallelogram
