Respuesta :

Part 3

we know that

If EF is a bisector

then

mand

msubstitute

msubstitute the given values

5x+19=2(3x+1)

solve for x

5x+19=6x+2

6x-5x=19-2

x=17

Part 4

we have that

If EF is a bisector

then

msubstitute the given values

5x-3=2x+15

solve for x

5x-2x=15+3

3x=18

x=6