Given the expression:
[tex](3x-4y^2)(3x+4y^2)[/tex]
From the difference of squares identity:
[tex](a+b)(a-b)=a^2-b^2[/tex]
From the problem, we identify:
[tex]\begin{gathered} a=3x \\ b=4y^2 \end{gathered}[/tex]
Finally, using the identity:
[tex]\begin{gathered} (3x-4y^2)(3x+4y^2)=(3x)^2-(4y^2)^2 \\ \\ \therefore9x^2-16x^4 \end{gathered}[/tex]
