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The weight of oranges growing in an orchard is normally distributed with a meanweight of 4.5 oz. and a standard deviation of 1 oz. Using the empirical rule, whatpercentage of the oranges from the orchard weigh between 3.5 oz. and 5.5 oz.?Answer:Submit Answer

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ANSWER:

68.26%

STEP-BY-STEP EXPLANATION:

Given:

mean = 4.5 oz

standard deviation = 1 oz

x = P(3.5 < x < 5.5)

The, by empirical rule solve as,

[tex]\begin{gathered} P\mleft(3.5We calculate the values of z by means of the following table:

Replacing:

[tex]\begin{gathered} P(3.5Therefore, the percentage is 68.26%

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