Assume that the cost of the small box is x and the large box is y
Since Jade sold 16 small boxes and 12 larger boxes for 344, then
[tex]16x+12y=344(1)[/tex]Since Alberts sold 8 small boxes and 8 larger boxes for 208, then
[tex]8x+8y=208(2)[/tex]Now, we have a system of equations to solve it
Multiply equation (2) by -2
[tex]\begin{gathered} -2(8x)+(-2)(8y)=-2(208) \\ -16x-16y=-416(3) \end{gathered}[/tex]Add equations (1) and (3) to eliminate x
[tex]\begin{gathered} (16x-16x)+(12y-16y)=(344-416) \\ -4y=-72 \end{gathered}[/tex]Divide both sides by -4
[tex]\begin{gathered} \frac{-4y}{-4}=\frac{-72}{-4} \\ y=18 \end{gathered}[/tex]Substitute the value of y in equation
