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A basketball team sells tickets that cost $10, $20 or for VIP seats. $30. The team has sold 3138 tickets overall It has sold 160 more $20 tickets than $10 tickets. The total sales are $59.060. How manytickets of each kind have been sold?How many $10 tickets were sold?

Respuesta :

Let

x -----> number of $10 tickets sold

y -----> number of $20 tickets sold

z -----> number of $30 tickets sold

we have that

x+y+z=3138 -------> equation A

10x+20y+30z=59060 -------> equation B

y=x+160 -----> equation C

Solve the system

using a 3x3 system of equations solver

x=1,116

y=1,276

z=746

therefore

number of $10 tickets sold was 1,116

number of $20 tickets sold was 1,276

number of $30 tickets sold was 746

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