The points are given C, D,E which are collinear .
Apply the internal division formula.
[tex]x=\frac{mx_2+nx_1}{m+n},y=\frac{my_2+ny_1}{m+n}[/tex]
From the given data , the coordinate of x is.
[tex]4=\frac{3x+5}{3+5}\Rightarrow4=\frac{3x+5}{8}[/tex][tex]32=3x+5\Rightarrow x=9[/tex]
From the given data, the coordinate of y is .
[tex]5=\frac{3y+40}{8}\Rightarrow40=3y+40[/tex][tex]y=0[/tex]
Hence the value of x is 9 and y is 0.
