Given:
Dimensions of building = 740 ft by 800ft
1 inch represents 8 ft
Find-:
Dimension of building in inch.
Explanation:-
1 inch represents 8 feet
[tex]\begin{gathered} 1\text{ inch = }8\text{ ft} \\ \\ 1\text{ }ft\text{ }=\frac{1}{8}\text{ inch} \end{gathered}[/tex]Dimension is 740 ft by 800 ft
length is 740 ft so,
[tex]\begin{gathered} 1\text{ }ft\text{ }=\frac{1}{8}\text{ inch} \\ \\ 1\times740\text{ }ft\text{ }=\frac{1}{8}\times740\text{ inch} \\ \\ 740\text{ }ft\text{ }=\frac{740}{8}\text{ inch} \\ \\ 740\text{ }ft\text{ }=92.5\text{ inch} \end{gathered}[/tex]The length is 92.5 inch
The breadth of thebuilding is 800 fts o,
[tex]\begin{gathered} 1\text{ }ft\text{ }=\frac{1}{8}\text{ inch} \\ \\ 1\times800\text{ }ft\text{ }=\frac{1}{8}\times800\text{ inch} \\ \\ 800\text{ }ft\text{ }=\frac{800}{8}\text{ inch} \\ \\ 800\text{ }ft=100\text{ inch} \end{gathered}[/tex]The breadth is 100 inch.